A(2y-5)=3(4y+7)

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Solution for A(2y-5)=3(4y+7) equation: 



(2A-5)=3(4A+7)

We move all terms to the left:

(2A-5)-(3(4A+7))=0

We get rid of parentheses

2A-(3(4A+7))-5=0



We calculate terms in parentheses: -(3(4A+7)), so:

3(4A+7)

We multiply parentheses

12A+21

Back to the equation:

-(12A+21)



We get rid of parentheses

2A-12A-21-5=0

We add all the numbers together, and all the variables

-10A-26=0

We move all terms containing A to the left, all other terms to the right

-10A=26

A=26/-10

A=-2+3/5

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