A(3)=-3+(n-1)(4)

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Solution for A(3)=-3+(n-1)(4) equation: 



(3)=-3+(A-1)(4)

We move all terms to the left:

(3)-(-3+(A-1)(4))=0



We calculate terms in parentheses: -(-3+(A-1)4), so:

-3+(A-1)4

determiningTheFunctionDomain
(A-1)4-3

We multiply parentheses

4A-4-3

We add all the numbers together, and all the variables

4A-7

Back to the equation:

-(4A-7)



We get rid of parentheses

-4A+7+3=0

We add all the numbers together, and all the variables

-4A+10=0

We move all terms containing A to the left, all other terms to the right

-4A=-10

A=-10/-4

A=2+1/2

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