A(3)=-3+(n-1)(6)

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Solution for A(3)=-3+(n-1)(6) equation: 



(3)=-3+(A-1)(6)

We move all terms to the left:

(3)-(-3+(A-1)(6))=0



We calculate terms in parentheses: -(-3+(A-1)6), so:

-3+(A-1)6

determiningTheFunctionDomain
(A-1)6-3

We multiply parentheses

6A-6-3

We add all the numbers together, and all the variables

6A-9

Back to the equation:

-(6A-9)



We get rid of parentheses

-6A+9+3=0

We add all the numbers together, and all the variables

-6A+12=0

We move all terms containing A to the left, all other terms to the right

-6A=-12

A=-12/-6

A=+2

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