A(3x+9)=15x+45

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Solution for A(3x+9)=15x+45 equation: 



(3A+9)=15A+45

We move all terms to the left:

(3A+9)-(15A+45)=0

We get rid of parentheses

3A-15A+9-45=0

We add all the numbers together, and all the variables

-12A-36=0

We move all terms containing A to the left, all other terms to the right

-12A=36

A=36/-12

A=-3

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