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(5)=3.14A^2
We move all terms to the left:
(5)-(3.14A^2)=0
We get rid of parentheses
-3.14A^2+5=0
a = -3.14; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-3.14)·5
Δ = 62.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{62.8}}{2*-3.14}=\frac{0-\sqrt{62.8}}{-6.28} =-\frac{\sqrt{}}{-6.28} $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{62.8}}{2*-3.14}=\frac{0+\sqrt{62.8}}{-6.28} =\frac{\sqrt{}}{-6.28} $
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