A(n)=12+(n-1)(-3)

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Solution for A(n)=12+(n-1)(-3) equation: 



(A)=12+(A-1)(-3)

We move all terms to the left:

(A)-(12+(A-1)(-3))=0

We multiply parentheses ..

A-(12+(-3A+3))=0



We calculate terms in parentheses: -(12+(-3A+3)), so:

12+(-3A+3)

determiningTheFunctionDomain
(-3A+3)+12

We get rid of parentheses

-3A+3+12

We add all the numbers together, and all the variables

-3A+15

Back to the equation:

-(-3A+15)



We get rid of parentheses

A+3A-15=0

We add all the numbers together, and all the variables

4A-15=0

We move all terms containing A to the left, all other terms to the right

4A=15

A=15/4

A=3+3/4

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