A(n)=189+(n-1)10

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Solution for A(n)=189+(n-1)10 equation: 



(A)=189+(A-1)10

We move all terms to the left:

(A)-(189+(A-1)10)=0



We calculate terms in parentheses: -(189+(A-1)10), so:

189+(A-1)10

determiningTheFunctionDomain
(A-1)10+189

We multiply parentheses

10A-10+189

We add all the numbers together, and all the variables

10A+179

Back to the equation:

-(10A+179)



We get rid of parentheses

A-10A-179=0

We add all the numbers together, and all the variables

-9A-179=0

We move all terms containing A to the left, all other terms to the right

-9A=179

A=179/-9

A=-19+8/9

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