A(n)=22+(n-1)12

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Solution for A(n)=22+(n-1)12 equation: 



(A)=22+(A-1)12

We move all terms to the left:

(A)-(22+(A-1)12)=0



We calculate terms in parentheses: -(22+(A-1)12), so:

22+(A-1)12

determiningTheFunctionDomain
(A-1)12+22

We multiply parentheses

12A-12+22

We add all the numbers together, and all the variables

12A+10

Back to the equation:

-(12A+10)



We get rid of parentheses

A-12A-10=0

We add all the numbers together, and all the variables

-11A-10=0

We move all terms containing A to the left, all other terms to the right

-11A=10

A=10/-11

A=-10/11

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