A(n)=3+(n-1)(11)

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Solution for A(n)=3+(n-1)(11) equation: 



(A)=3+(A-1)(11)

We move all terms to the left:

(A)-(3+(A-1)(11))=0



We calculate terms in parentheses: -(3+(A-1)11), so:

3+(A-1)11

determiningTheFunctionDomain
(A-1)11+3

We multiply parentheses

11A-11+3

We add all the numbers together, and all the variables

11A-8

Back to the equation:

-(11A-8)



We get rid of parentheses

A-11A+8=0

We add all the numbers together, and all the variables

-10A+8=0

We move all terms containing A to the left, all other terms to the right

-10A=-8

A=-8/-10

A=4/5

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