A(n)=3+(n-1)+(5)

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Solution for A(n)=3+(n-1)+(5) equation: 



(A)=3+(A-1)+(5)

We move all terms to the left:

(A)-(3+(A-1)+(5))=0



We calculate terms in parentheses: -(3+(A-1)+5), so:

3+(A-1)+5

determiningTheFunctionDomain
(A-1)+3+5

We add all the numbers together, and all the variables

(A-1)+8

We get rid of parentheses

A-1+8

We add all the numbers together, and all the variables

A+7

Back to the equation:

-(A+7)



We get rid of parentheses

A-A-7=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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