A(n)=4+(n-1)(9)

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Solution for A(n)=4+(n-1)(9) equation: 



(A)=4+(A-1)(9)

We move all terms to the left:

(A)-(4+(A-1)(9))=0



We calculate terms in parentheses: -(4+(A-1)9), so:

4+(A-1)9

determiningTheFunctionDomain
(A-1)9+4

We multiply parentheses

9A-9+4

We add all the numbers together, and all the variables

9A-5

Back to the equation:

-(9A-5)



We get rid of parentheses

A-9A+5=0

We add all the numbers together, and all the variables

-8A+5=0

We move all terms containing A to the left, all other terms to the right

-8A=-5

A=-5/-8

A=5/8

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