A(x)=(x+3)+(3x-5)

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Solution for A(x)=(x+3)+(3x-5) equation: 



(A)=(A+3)+(3A-5)

We move all terms to the left:

(A)-((A+3)+(3A-5))=0



We calculate terms in parentheses: -((A+3)+(3A-5)), so:

(A+3)+(3A-5)

We get rid of parentheses

A+3A+3-5

We add all the numbers together, and all the variables

4A-2

Back to the equation:

-(4A-2)



We get rid of parentheses

A-4A+2=0

We add all the numbers together, and all the variables

-3A+2=0

We move all terms containing A to the left, all other terms to the right

-3A=-2

A=-2/-3

A=2/3

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