A(x)=2(20-2x)(30-2x)+2(20-2x)x+2(30-2x)x

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Solution for A(x)=2(20-2x)(30-2x)+2(20-2x)x+2(30-2x)x equation: 



(A)=2(20-2A)(30-2A)+2(20-2A)A+2(30-2A)A

We move all terms to the left:

(A)-(2(20-2A)(30-2A)+2(20-2A)A+2(30-2A)A)=0

We add all the numbers together, and all the variables

A-(2(-2A+20)(-2A+30)+2(-2A+20)A+2(-2A+30)A)=0

We multiply parentheses ..

-(2(+4A^2-60A-40A+600)+2(-2A+20)A+2(-2A+30)A)+A=0



We calculate terms in parentheses: -(2(+4A^2-60A-40A+600)+2(-2A+20)A+2(-2A+30)A), so:

2(+4A^2-60A-40A+600)+2(-2A+20)A+2(-2A+30)A

We multiply parentheses

8A^2-4A^2-4A^2-120A-80A+40A+60A+1200

We add all the numbers together, and all the variables

-100A+1200

Back to the equation:

-(-100A+1200)



We add all the numbers together, and all the variables

A-(-100A+1200)=0

We get rid of parentheses

A+100A-1200=0

We add all the numbers together, and all the variables

101A-1200=0

We move all terms containing A to the left, all other terms to the right

101A=1200

A=1200/101

A=11+89/101

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