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(A)=A(300-2A)
We move all terms to the left:
(A)-(A(300-2A))=0
We add all the numbers together, and all the variables
A-(A(-2A+300))=0
We calculate terms in parentheses: -(A(-2A+300)), so:We get rid of parentheses
A(-2A+300)
We multiply parentheses
-2A^2+300A
Back to the equation:
-(-2A^2+300A)
2A^2-300A+A=0
We add all the numbers together, and all the variables
2A^2-299A=0
a = 2; b = -299; c = 0;
Δ = b2-4ac
Δ = -2992-4·2·0
Δ = 89401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{89401}=299$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-299)-299}{2*2}=\frac{0}{4} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-299)+299}{2*2}=\frac{598}{4} =149+1/2 $
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