A(x)=x(50-5x)

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Solution for A(x)=x(50-5x) equation:



(A)=A(50-5A)
We move all terms to the left:
(A)-(A(50-5A))=0
We add all the numbers together, and all the variables
A-(A(-5A+50))=0
We calculate terms in parentheses: -(A(-5A+50)), so:
A(-5A+50)
We multiply parentheses
-5A^2+50A
Back to the equation:
-(-5A^2+50A)
We get rid of parentheses
5A^2-50A+A=0
We add all the numbers together, and all the variables
5A^2-49A=0
a = 5; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·5·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*5}=\frac{0}{10} =0 $
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*5}=\frac{98}{10} =9+4/5 $

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