A+1/5b=2

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Solution for A+1/5b=2 equation: 



+1/5A=2

We move all terms to the left:

+1/5A-(2)=0



Domain of the equation: 5A!=0

A!=0/5

A!=0

A∈R



We multiply all the terms by the denominator


-2*5A+1=0

Wy multiply elements

-10A+1=0

We move all terms containing A to the left, all other terms to the right

-10A=-1

A=-1/-10

A=1/10

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