A+27=5/2h

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Solution for A+27=5/2h equation: 



+27=5/2A

We move all terms to the left:

+27-(5/2A)=0



Domain of the equation: 2A)!=0

A!=0/1

A!=0

A∈R



We add all the numbers together, and all the variables

-(+5/2A)+27=0

We get rid of parentheses

-5/2A+27=0

We multiply all the terms by the denominator


27*2A-5=0

Wy multiply elements

54A-5=0

We move all terms containing A to the left, all other terms to the right

54A=5

A=5/54

A=5/54

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