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+5=1/3(3A+15)
We move all terms to the left:
+5-(1/3(3A+15))=0
Domain of the equation: 3(3A+15))!=0We multiply all the terms by the denominator
A∈R
-(1+5*3(3A+15))=0
We calculate terms in parentheses: -(1+5*3(3A+15)), so:We add all the numbers together, and all the variables
1+5*3(3A+15)
determiningTheFunctionDomain 5*3(3A+15)+1
Wy multiply elements
15A(3+1
Back to the equation:
-(15A(3+1)
-(15A4=0
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