A+5x2/3=9

Solution for A+5x2/3=9 equation:

+5A^2/3=9

We move all terms to the left:

+5A^2/3-(9)=0

We multiply all the terms by the denominator


5A^2-9*3=0

We add all the numbers together, and all the variables

5A^2-27=0

a = 5; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·5·(-27)
Δ = 540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{540}=\sqrt{36*15}=\sqrt{36}*\sqrt{15}=6\sqrt{15}$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{15}}{2*5}=\frac{0-6\sqrt{15}}{10}
=-\frac{6\sqrt{15}}{10}
=-\frac{3\sqrt{15}}{5}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{15}}{2*5}=\frac{0+6\sqrt{15}}{10}
=\frac{6\sqrt{15}}{10}
=\frac{3\sqrt{15}}{5}
$