If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x-(3/(x^2))
1/((2*x+1)^3)
2/x+1 > 0
1;4;1;3;5;1
(x+3)^2 = (x-1)^2
| 2x+17=2x+19 | | -0.5(x+2)+1.5x=3 | | 5x+7*5x+7*5x+7= | | 8x-41+2x+1=180 | | 12y-8=7 | | 3(x-6)-4(x-10)= | | 9+3u+1-2u= | | 9x+6=3x+2 | | x=-3+8x+5+4x | | 0.25+0.5+x=-0.75 | | -16=6k-2k | | Y-2=-2(x+6) | | 15-4a+20=7 | | 6/12=3/4 | | 3+6a=33 | | Sin(x+10)=cos(3x-20) | | -5+-3x=-32 | | Y-6=-2(x-4) | | 3x-7+35=23+4x | | -4(x-6)=22 | | 3x+15=75-7x | | x^2+20=-x | | -(-5+8a)+8= | | -2(x-8)=0 | | -7x+11=19-z | | 2.4+1.2(n+2)=6 | | 4.5(2x+4)=4x+18+15x | | Y=a+b(X) | | h=25t+5t^2+0.2 | | 3(2x-5)=2(x+10)+1 | | J+(14)=1 | | 5/22/7/22 |