A3f+B8=Y7f+Z11

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Solution for A3f+B8=Y7f+Z11 equation: 



3A+8=7A+11

We move all terms to the left:

3A+8-(7A+11)=0

We get rid of parentheses

3A-7A-11+8=0

We add all the numbers together, and all the variables

-4A-3=0

We move all terms containing A to the left, all other terms to the right

-4A=3

A=3/-4

A=-3/4

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