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=(10A+12A)6A
We move all terms to the left:
-((10A+12A)6A)=0
We add all the numbers together, and all the variables
-((+22A)6A)=0
We calculate terms in parentheses: -((+22A)6A), so:a = -132; b = 0; c = 0;
(+22A)6A
We multiply parentheses
132A^2
Back to the equation:
-(132A^2)
Δ = b2-4ac
Δ = 02-4·(-132)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$A=\frac{-b}{2a}=\frac{0}{-264}=0$
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