A=(2d-b+c)/3

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Solution for A=(2d-b+c)/3 equation: 


x in (-oo:+oo)

A = (c-b+2*d)/3 // - (c-b+2*d)/3

A-((c-b+2*d)/3) = 0

(-1*(c-b+2*d))/3+A = 0

(-1*(c-b+2*d))/3+(3*A)/3 = 0

3*A-1*(c-b+2*d) = 0

3*A+b-c-2*d = 0

(3*A+b-c-2*d)/3 = 0

(3*A+b-c-2*d)/3 = 0 // * 3

3*A+b-c-2*d = 0

x belongs to the empty set

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