A=(3x+5)2x

Solution for A=(3x+5)2x equation:

=(3A+5)2A

We move all terms to the left:

-((3A+5)2A)=0


We calculate terms in parentheses: -((3A+5)2A), so:

(3A+5)2A

We multiply parentheses

6A^2+10A

Back to the equation:

-(6A^2+10A)


We get rid of parentheses

-6A^2-10A=0

a = -6; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-6)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-6}=\frac{0}{-12}
=0
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-6}=\frac{20}{-12}
=-1+2/3
$