A=(3x+5)B=(2x-15)A+B=90

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Solution for A=(3x+5)B=(2x-15)A+B=90 equation: 



=(3A+5)=(2A-15)+=90

We move all terms to the left:

-((3A+5))=0



We calculate terms in parentheses: -((3A+5)), so:

(3A+5)

We get rid of parentheses

3A+5

Back to the equation:

-(3A+5)



We get rid of parentheses

-3A-5=0

We move all terms containing A to the left, all other terms to the right

-3A=5

A=5/-3

A=-1+2/3

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