A=(4k-4)B=(3-3k)

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Solution for A=(4k-4)B=(3-3k) equation:



=(4A-4)=(3-3A)
We move all terms to the left:
-((4A-4))=0
We calculate terms in parentheses: -((4A-4)), so:
(4A-4)
We get rid of parentheses
4A-4
Back to the equation:
-(4A-4)
We get rid of parentheses
-4A+4=0
We move all terms containing A to the left, all other terms to the right
-4A=-4
A=-4/-4
A=1

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