A=(6x+5)(4x+1)

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Solution for A=(6x+5)(4x+1) equation:



=(6A+5)(4A+1)
We move all terms to the left:
-((6A+5)(4A+1))=0
We multiply parentheses ..
-((+24A^2+6A+20A+5))=0
We calculate terms in parentheses: -((+24A^2+6A+20A+5)), so:
(+24A^2+6A+20A+5)
We get rid of parentheses
24A^2+6A+20A+5
We add all the numbers together, and all the variables
24A^2+26A+5
Back to the equation:
-(24A^2+26A+5)
We get rid of parentheses
-24A^2-26A-5=0
a = -24; b = -26; c = -5;
Δ = b2-4ac
Δ = -262-4·(-24)·(-5)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*-24}=\frac{12}{-48} =-1/4 $
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*-24}=\frac{40}{-48} =-5/6 $

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