A=(6x+8)(4x-10)

Solution for A=(6x+8)(4x-10) equation:

=(6A+8)(4A-10)

We move all terms to the left:

-((6A+8)(4A-10))=0

We multiply parentheses ..

-((+24A^2-60A+32A-80))=0


We calculate terms in parentheses: -((+24A^2-60A+32A-80)), so:

(+24A^2-60A+32A-80)

We get rid of parentheses

24A^2-60A+32A-80

We add all the numbers together, and all the variables

24A^2-28A-80

Back to the equation:

-(24A^2-28A-80)


We get rid of parentheses

-24A^2+28A+80=0

a = -24; b = 28; c = +80;
Δ = b2-4ac
Δ = 282-4·(-24)·80
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-92}{2*-24}=\frac{-120}{-48}
=2+1/2
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+92}{2*-24}=\frac{64}{-48}
=-1+1/3
$