A=(7x-3)(7x+3)-(3x+4)2

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Solution for A=(7x-3)(7x+3)-(3x+4)2 equation: 



=(7A-3)(7A+3)-(3A+4)2

We move all terms to the left:

-((7A-3)(7A+3)-(3A+4)2)=0

We use the square of the difference formula

49A^2+9=0

a = 49; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·49·9
Δ = -1764
Delta is less than zero, so there is no solution for the equation

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