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=(8A+6)(6A+4)
We move all terms to the left:
-((8A+6)(6A+4))=0
We multiply parentheses ..
-((+48A^2+32A+36A+24))=0
We calculate terms in parentheses: -((+48A^2+32A+36A+24)), so:We get rid of parentheses
(+48A^2+32A+36A+24)
We get rid of parentheses
48A^2+32A+36A+24
We add all the numbers together, and all the variables
48A^2+68A+24
Back to the equation:
-(48A^2+68A+24)
-48A^2-68A-24=0
a = -48; b = -68; c = -24;
Δ = b2-4ac
Δ = -682-4·(-48)·(-24)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-4}{2*-48}=\frac{64}{-96} =-2/3 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+4}{2*-48}=\frac{72}{-96} =-3/4 $
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