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=(A-1)(1-A)
We move all terms to the left:
-((A-1)(1-A))=0
We add all the numbers together, and all the variables
-((A-1)(-1A+1))=0
We multiply parentheses ..
-((-1A^2+A+A-1))=0
We calculate terms in parentheses: -((-1A^2+A+A-1)), so:We get rid of parentheses
(-1A^2+A+A-1)
We get rid of parentheses
-1A^2+A+A-1
We add all the numbers together, and all the variables
-1A^2+2A-1
Back to the equation:
-(-1A^2+2A-1)
1A^2-2A+1=0
We add all the numbers together, and all the variables
A^2-2A+1=0
a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$A=\frac{-b}{2a}=\frac{2}{2}=1$
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