A=(x+2)*(x+2)

Solution for A=(x+2)*(x+2) equation:

=(A+2)(A+2)

We move all terms to the left:

-((A+2)(A+2))=0

We multiply parentheses ..

-((+A^2+2A+2A+4))=0


We calculate terms in parentheses: -((+A^2+2A+2A+4)), so:

(+A^2+2A+2A+4)

We get rid of parentheses

A^2+2A+2A+4

We add all the numbers together, and all the variables

A^2+4A+4

Back to the equation:

-(A^2+4A+4)


We get rid of parentheses

-A^2-4A-4=0

We add all the numbers together, and all the variables

-1A^2-4A-4=0

a = -1; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·(-1)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{4}{-2}=-2$