A=(x2+B)

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Solution for A=(x2+B) equation:



=(A2+)
We move all terms to the left:
-((A2+))=0
We add all the numbers together, and all the variables
-((+A^2+))=0
We calculate terms in parentheses: -((+A^2+)), so:
(+A^2+)
We get rid of parentheses
A^2+
We add all the numbers together, and all the variables
A^2
Back to the equation:
-(A^2)
We add all the numbers together, and all the variables
-1A^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{-2}=0$

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