A=(x2+B)

Solution for A=(x2+B) equation:

=(A2+)

We move all terms to the left:

-((A2+))=0

We add all the numbers together, and all the variables

-((+A^2+))=0


We calculate terms in parentheses: -((+A^2+)), so:

(+A^2+)

We get rid of parentheses

A^2+

We add all the numbers together, and all the variables

A^2

Back to the equation:

-(A^2)


We add all the numbers together, and all the variables

-1A^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{-2}=0$