A=-2x(3x-13)

Solution for A=-2x(3x-13) equation:

=-2A(3A-13)

We move all terms to the left:

-(-2A(3A-13))=0


We calculate terms in parentheses: -(-2A(3A-13)), so:

-2A(3A-13)

We multiply parentheses

-6A^2+26A

Back to the equation:

-(-6A^2+26A)


We get rid of parentheses

6A^2-26A=0

a = 6; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·6·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*6}=\frac{0}{12}
=0
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*6}=\frac{52}{12}
=4+1/3
$