A=1/2(5x+35)(x+2)

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Solution for A=1/2(5x+35)(x+2) equation: 



=1/2(5A+35)(A+2)

We move all terms to the left:

-(1/2(5A+35)(A+2))=0



Domain of the equation: 2(5A+35)(A+2))!=0

A∈R



We multiply parentheses ..

-(1/2(+5A^2+10A+35A+70))=0

We multiply all the terms by the denominator


-(1=0

We add all the numbers together, and all the variables

=0

A=0/1

A=0

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