A=1/2(b1+b2)

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Solution for A=1/2(b1+b2) equation: 


x in (-oo:+oo)

A = (1/2)*(b^2+b^1) // - (1/2)*(b^2+b^1)

A-((1/2)*(b^2+b^1)) = 0

(-1/2)*(b^2+b)+A = 0

A-1/2*(b^2+b) = 0

A-1/2*(b^2+b) = 0

A-1/2*b^2-1/2*b = 0

A-1/2*b^2-1/2*b = 0

x belongs to the empty set

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