A=1/2(y)(4y+y)

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Solution for A=1/2(y)(4y+y) equation:



=1/2(A)(4A+A)
We move all terms to the left:
-(1/2(A)(4A+A))=0
Domain of the equation: 2A(4A+A))!=0
A∈R
We add all the numbers together, and all the variables
-(1/2A(+5A))=0
We multiply all the terms by the denominator
-(1=0
We add all the numbers together, and all the variables
=0
A=0/1
A=0

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