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x in (-oo:+oo)
A = (2/3)*(a+b+3) // - (2/3)*(a+b+3)
A-((2/3)*(a+b+3)) = 0
(-2/3)*(a+b+3)+A = 0
A-2/3*(a+b+3) = 0
A-2/3*(a+b+3) = 0
A-2/3*a-2/3*b-2 = 0
A-2/3*a-2/3*b-2 = 0
x belongs to the empty set
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