A=2/3(a+b+3)

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Solution for A=2/3(a+b+3) equation: 


x in (-oo:+oo)

A = (2/3)*(a+b+3) // - (2/3)*(a+b+3)

A-((2/3)*(a+b+3)) = 0

(-2/3)*(a+b+3)+A = 0

A-2/3*(a+b+3) = 0

A-2/3*(a+b+3) = 0

A-2/3*a-2/3*b-2 = 0

A-2/3*a-2/3*b-2 = 0

x belongs to the empty set

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