A=3(1+4x)+11+2x

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Solution for A=3(1+4x)+11+2x equation: 



=3(1+4A)+11+2A

We move all terms to the left:

-(3(1+4A)+11+2A)=0

We add all the numbers together, and all the variables

-(3(4A+1)+11+2A)=0



We calculate terms in parentheses: -(3(4A+1)+11+2A), so:

3(4A+1)+11+2A

determiningTheFunctionDomain
3(4A+1)+2A+11

We add all the numbers together, and all the variables

2A+3(4A+1)+11

We multiply parentheses

2A+12A+3+11

We add all the numbers together, and all the variables

14A+14

Back to the equation:

-(14A+14)



We get rid of parentheses

-14A-14=0

We move all terms containing A to the left, all other terms to the right

-14A=14

A=14/-14

A=-1

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