A=3(1+y)+5(2y-2)

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Solution for A=3(1+y)+5(2y-2) equation:



=3(1+A)+5(2A-2)
We move all terms to the left:
-(3(1+A)+5(2A-2))=0
We add all the numbers together, and all the variables
-(3(A+1)+5(2A-2))=0
We calculate terms in parentheses: -(3(A+1)+5(2A-2)), so:
3(A+1)+5(2A-2)
We multiply parentheses
3A+10A+3-10
We add all the numbers together, and all the variables
13A-7
Back to the equation:
-(13A-7)
We get rid of parentheses
-13A+7=0
We move all terms containing A to the left, all other terms to the right
-13A=-7
A=-7/-13
A=7/13

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