A=3(b+5)

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Solution for A=3(b+5) equation: 



=3(A+5)

We move all terms to the left:

-(3(A+5))=0



We calculate terms in parentheses: -(3(A+5)), so:

3(A+5)

We multiply parentheses

3A+15

Back to the equation:

-(3A+15)



We get rid of parentheses

-3A-15=0

We move all terms containing A to the left, all other terms to the right

-3A=15

A=15/-3

A=-5

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