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=3A(A-6)
We move all terms to the left:
-(3A(A-6))=0
We calculate terms in parentheses: -(3A(A-6)), so:We get rid of parentheses
3A(A-6)
We multiply parentheses
3A^2-18A
Back to the equation:
-(3A^2-18A)
-3A^2+18A=0
a = -3; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-3)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-3}=\frac{-36}{-6} =+6 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-3}=\frac{0}{-6} =0 $
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