A=3x+40,C=x,B=11x-60=180

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Solution for A=3x+40,C=x,B=11x-60=180 equation: 



=3A+40.=A.=11A-60=180

We move all terms to the left:

-(3A+40.)=0

We add all the numbers together, and all the variables

-(3A+40)=0

We get rid of parentheses

-3A-40=0

We move all terms containing A to the left, all other terms to the right

-3A=40

A=40/-3

A=-13+1/3

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