A=3x-5+5(2x-2)

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Solution for A=3x-5+5(2x-2) equation: 



=3A-5+5(2A-2)

We move all terms to the left:

-(3A-5+5(2A-2))=0



We calculate terms in parentheses: -(3A-5+5(2A-2)), so:

3A-5+5(2A-2)

determiningTheFunctionDomain
3A+5(2A-2)-5

We multiply parentheses

3A+10A-10-5

We add all the numbers together, and all the variables

13A-15

Back to the equation:

-(13A-15)



We get rid of parentheses

-13A+15=0

We move all terms containing A to the left, all other terms to the right

-13A=-15

A=-15/-13

A=1+2/13

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