A=3x2=6x14=84x6+2+2=100

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Solution for A=3x2=6x14=84x6+2+2=100 equation: 



=3A^2=6A^14=84A^6+2+2=100

We move all terms to the left:

-(3A^2)=0

a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{-6}=0$

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