A=4w2-17w-4

Solution for A=4w2-17w-4 equation:

=4A^2-17A-4

We move all terms to the left:

-(4A^2-17A-4)=0

We get rid of parentheses

-4A^2+17A+4=0

a = -4; b = 17; c = +4;
Δ = b2-4ac
Δ = 172-4·(-4)·4
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{353}}{2*-4}=\frac{-17-\sqrt{353}}{-8}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{353}}{2*-4}=\frac{-17+\sqrt{353}}{-8}
$