A=4x(9x+6)

Solution for A=4x(9x+6) equation:

=4A(9A+6)

We move all terms to the left:

-(4A(9A+6))=0


We calculate terms in parentheses: -(4A(9A+6)), so:

4A(9A+6)

We multiply parentheses

36A^2+24A

Back to the equation:

-(36A^2+24A)


We get rid of parentheses

-36A^2-24A=0

a = -36; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·(-36)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*-36}=\frac{0}{-72}
=0
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*-36}=\frac{48}{-72}
=-2/3
$