A=4x,B=3x+12,C=x+8

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Solution for A=4x,B=3x+12,C=x+8 equation: 



=4A.=3A+12.=A+8

We move all terms to the left:

-(4A.)=0

We add all the numbers together, and all the variables

-(+4A.)=0

We get rid of parentheses

-4A.=0

A=0/1

A=0

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