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=4A^2-280A+4800
We move all terms to the left:
-(4A^2-280A+4800)=0
We get rid of parentheses
-4A^2+280A-4800=0
a = -4; b = 280; c = -4800;
Δ = b2-4ac
Δ = 2802-4·(-4)·(-4800)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(280)-40}{2*-4}=\frac{-320}{-8} =+40 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(280)+40}{2*-4}=\frac{-240}{-8} =+30 $
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