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=5A(3A+2)
We move all terms to the left:
-(5A(3A+2))=0
We calculate terms in parentheses: -(5A(3A+2)), so:We get rid of parentheses
5A(3A+2)
We multiply parentheses
15A^2+10A
Back to the equation:
-(15A^2+10A)
-15A^2-10A=0
a = -15; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·(-15)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*-15}=\frac{0}{-30} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*-15}=\frac{20}{-30} =-2/3 $
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